2 liters of agas is enclosed in a vessel at a pressure of 760 mm Hg. If the temperature remains constant,
calculate the pressure when the volume changes to 40 dm3.
V = 2 litres
P = 760 mm
V1 = 4000 m3 [1 dm3 = 4 litres]
P1= ?
\begin{array}{l} \frac{\mathrm{PV}}{\mathrm{T}}=\frac{\mathrm{P} 1 \mathrm{V} 1}{\mathrm{Tl}} \\ \frac{760 \mathrm{x} 2}{\mathrm{T}}=\frac{\mathrm{Pl} \times 4}{\mathrm{T} 1} \end{array}
P1= 760/2 = 380mm
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