A certain mass of a gas occupies 2 liters at 27oC and 100 pascals. Find the temperature when volume and pressure become half of their initial values
V = 2 litres
P = 100 Pa
T = 300 K
T1 =?
P1 = 1/2 x 100 = 50 Pa
V1 = 1/2 x 2
V1 = 1 litre
From Gas equation
PV/T = P1V1/T1
100 x 2/300 = 50 x 1/T1
T1 = 75 K
T1 = 75-273
= - 198oc
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