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Chapter 7 Study Of Gas Laws | Number Problems

Question 15

15. What temperature would be necessary to double the volume of a gas, initially at S.T.P., if the pressure is

decreased to 50%.

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V = 50 cm3

P = 750 - 14 = 736 mm

T = 290 K

P1 = 760 mm

V1=?

T1 = 273 K

Using gas equation

PV/T = P1V1/T1

736/290 = 760 x V1/273

V1= 45.6 cm3

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Question 15

15. What temperature would be necessary to double the volume of a gas, initially at S.T.P., if the pressure is

decreased to 50%.

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

V = 50 cm3

P = 750 - 14 = 736 mm

T = 290 K

P1 = 760 mm

V1=?

T1 = 273 K

Using gas equation

PV/T = P1V1/T1

736/290 = 760 x V1/273

V1= 45.6 cm3

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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