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Selina Solutions Class 9 Chemistry Solutions for Exercise Number Problems in Chapter 7 - Chapter 7 Study Of Gas Laws
Question 1 Number Problems
What will be the minimum pressure required to compress 500 dm3 of air at 1 bar to 200 dm3 temperature
remaining constant.
Answer:
V1 = 500 dm3
P1 = 1 bar
T1 = 273 K
V2 = 200 dm3
T2 = 273 K
P2= ?
P1V1 = P2V2
T1 T2
500x1 = P2 x 200
273 273
P2= 500
200
= 2.5 bar
Video transcript
"hey kids i am mansi from leader learning
today we are going to do this numerical
which will be of
a great use to you now what will be the
minimum pressure
required to compress 500 dm
cube which is decimeter cube of air at 1
bar
to 200 decimeter cube temperature
remaining constant
here we have to find the pressure and we
know by the formula
that p1 into v1 which is pressure of
pressure volume upon temperature
is equal to p2
v2 upon t2
now now by this formula pressure 1
is said to be 1 bar while volume 1
is said to be 500. t1
is said to be 273 which is the
standard one now p2 we have to find
v2 is given as 200
and t2 is also 273
we have to take a note here that units
are same hence there is
no requirement of any conversions
we'll simply find p2 by cross
multiplication
and we'll get the answer as 2.5
bar hence p2 is 2.5 bar
i hope you found this video useful for
more videos like these
subscribe to our channel and if you have
any questions
drop them down in the comment section
bye bye
"
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