Selina Solutions Class 9 Chemistry Solutions for Exercise 7 in Chapter 7 - Chapter 7 Study Of Gas Laws

Question 14 Exercise 7

(a) Define S.T.P.

(b) Why is it necessary to compare gases at S.T.P.?

Answer:

The temperature of 0°C or 273 K, the pressure of 76mm Hg or 1 atm is considered as standard temperature and

pressure.

It is necessary to compare gases at STP because the volume of a gas changes remarkably with a change in temperature.

Video transcript

"hey kids i am mansi from leader learning today we are going to do these questions question number one define stp which is standard temperature pressure the temperature of 0 degree celsius or 273 kelvin the pressure of 76 mm mercury or one atmospheric is considered as standard temperature and pressure now let's have a look at question 2 why is it necessary to compare gases at stp it is necessary to compare gases at stp because volume of gas changes remarkably with change in temperature hence it is necessary to compare gases at a standard temperature and pressure i hope you found this video useful for more videos subscribe to our channel bye"

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Exercises

Exercise 7

Number Problems

Chapters

Chapter 1 The Language Of Chemistry